20y^(3/2)/3=x

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Solution for 20y^(3/2)/3=x equation: 


x in (-oo:+oo)

(20*y^(3/2))/3 = x // - x

(20*y^(3/2))/3-x = 0

20/3*y^(3/2)-x = 0 // - 20/3*y^(3/2)

-x = -(20/3*y^(3/2)) // * -1

x = 20/3*y^(3/2)

x = 20/3*y^(3/2)

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